How to Distribute N Points on the Surface of a Sphere ?

The Volume of a Spherical Triangle

The volume of a spherical triangle ABC is the volume of the tetrahedron defined by A,B,C and the sphere's center O.
It can be calculated by the following formulas:
$\displaystyle \begin{array}{rl}
      V & = \frac{1}{6} \cdot A,B,C 
      \\& = \frac{1}{6} \cdot \sin a \cdot \sin h_a
      \\& = \frac{1}{6} \cdot \sin a \cdot \sin b \cdot \sin \gamma
      \\& = \frac{1}{6} \cdot \sqrt{1-(\cos ^2 a + \cos ^2 b + \cos ^2 c )+ 
                                2 \cdot \cos a \cdot \cos b \cdot \cos c }
      \\& = \frac{1}{6} \cdot \sqrt{ \sin s \cdot \sin (s-a)
                               \cdot \sin (s-b) \cdot \sin (s-c) }
      \\& = \frac{ 1 - (\cos ^2 \alpha + \cos ^2 \beta + \cos ^2 \gamma ) - 
                 2 \cdot \cos \alpha \cdot \cos \beta \cdot \cos \gamma }
               { 6 \cdot \sin \alpha \cdot \sin \beta \cdot \sin \gamma }
    \end{array}
The last formula can be deduced from V = sin a · sin b · sin γ by the use of the theorem of sine- and the theorem of the angle's cosine.

Conjecture 1:   The function

\begin{displaymath}
      V = V(x,y,z) = \frac{ 1 - (\cos ^2 x + \cos ^2 y + \cos ^2 z ) - 
                     2 \cdot \cos x \cdot \cos y \cdot \cos z }
                   { 6 \cdot \sin x \cdot \sin y \cdot \sin z }
\end{displaymath}

is strict concave for 0° < x,y,z < 180° and 0° < x+y+z < 540° .

Remarks:

Remarks: Literatur:
[1] Sigl, Rudolph
Ebene und Sphärische Trigonometrie
H.Wichmann-Verlag, Karlsruhe, 1977
[2] Wimmer, Lienhard:
Über das maximale Volumen der konvexen Hülle von Punkten auf der Einheitskugel
Dissertation, Salzburg, 1997

Lienhard Wimmer
2004-01-09